What is (10a^2b^3c)/(80(a^3-a^2b)) ?

The solution to (10a^2b^3c)/(80(a^3-a^2b)) is (b^3c)/(8(a-b))

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simplify (10a^2b^3c)/(80(a^3-a^2b))

simplify

\frac{10 a ^{2} b ^{3} c}{80 ( a ^{3} - a ^{2} b )}

\frac{b ^{3} c}{8 ( a - b )}

Solution steps

\frac{10 a ^{2} b ^{3} c}{80 ( a ^{3} - a ^{2} b )}

Factor the number:

80 = 10 \cdot 8

= \frac{10 a ^{2} b ^{3} c}{10 \cdot 8 ( a ^{3} - a ^{2} b )}

Cancel the common factor:

10

= \frac{a ^{2} b ^{3} c}{8 ( a ^{3} - a ^{2} b )}

Factor

a^{3} - a^{2} b : a^{2} (a - b)

= \frac{a ^{2} b ^{3} c}{8 a ^{2} ( a - b )}

Cancel the common factor:

a^{2}

= \frac{b ^{3} c}{8 ( a - b )}

\frac{n ^{2}}{9} + 2 mn + 9 m^{2}

x \frac{1}{3}

\frac{6 ( 2 a - 4 c ) - 6 ( 6 a - 4 b ) + 3 ( 4 b - 8 c )}{4}

\frac{x ^{2} + 7 x - 78}{x ^{2} - 36}

\frac{4 - 10 i}{- 3 - 7 i}

What is (10a^2b^3c)/(80(a^3-a^2b)) ?
The solution to (10a^2b^3c)/(80(a^3-a^2b)) is (b^3c)/(8(a-b))