What are the solutions to the equation x^2+6x+16=0 ?

The solutions to the equation x^2+6x+16=0 are x=-3+sqrt(7)i,x=-3-sqrt(7)i

Find the zeros of x^2+6x+16=0

The zeros of x^2+6x+16=0 are x=-3+sqrt(7)i,x=-3-sqrt(7)i

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x^{2} + 6 x + 16 = 0

x = - 3 + 7 i, x = - 3 - 7 i

Solution steps

x^{2} + 6 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 16 : 27 i

x_{1, 2} = \frac{- 6 \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 7 i}{2 \cdot 1}

x = \frac{- 6 + 2 7 i}{2 \cdot 1} : - 3 + 7 i

x = \frac{- 6 - 2 7 i}{2 \cdot 1} : - 3 - 7 i

The solutions to the quadratic equation are:

x = - 3 + 7 i, x = - 3 - 7 i

5 x^{2} + 25 x - 1500 = 0

4 x^{2} - 28 x + 24 = 0

(x + 4) (x + 9) (5 - x) \leq 0

\frac{1}{3} x^{2} - \frac{1}{9} x - \frac{10}{9} = 0

(- 3 + 6 i)^{2}

What are the solutions to the equation x^2+6x+16=0 ?
The solutions to the equation x^2+6x+16=0 are x=-3+sqrt(7)i,x=-3-sqrt(7)i
Find the zeros of x^2+6x+16=0
The zeros of x^2+6x+16=0 are x=-3+sqrt(7)i,x=-3-sqrt(7)i