What are the solutions to the equation 2d^2+3d-2=0 ?

The solutions to the equation 2d^2+3d-2=0 are d= 1/2 ,d=-2

Find the zeros of 2d^2+3d-2=0

The zeros of 2d^2+3d-2=0 are d= 1/2 ,d=-2

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2 d^{2} + 3 d - 2 = 0

d = \frac{1}{2}, d = - 2

Decimal Notation

d = 0.5, d = - 2

Solution steps

2 d^{2} + 3 d - 2 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 2) = 5

d_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 2}

Separate the solutions

d_{1} = \frac{- 3 + 5}{2 \cdot 2}, d_{2} = \frac{- 3 - 5}{2 \cdot 2}

d = \frac{- 3 + 5}{2 \cdot 2} : \frac{1}{2}

d = \frac{- 3 - 5}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

d = \frac{1}{2}, d = - 2

3 (x + 5) + 8 = - 4

b^{2} - 4 b - 21 = 0

(\frac{4 x ^{- 2} y ^{3}}{x y ^{- 4}})^{- 2}

a^{2} + 14 a - 51 = 0

(\frac{x}{4})^{2}

What are the solutions to the equation 2d^2+3d-2=0 ?
The solutions to the equation 2d^2+3d-2=0 are d= 1/2 ,d=-2
Find the zeros of 2d^2+3d-2=0
The zeros of 2d^2+3d-2=0 are d= 1/2 ,d=-2