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Popular >

3|x-1|>= 12

Solution

3 ∣ x - 1 ∣ \geq 12

Solution

x \leq - 3 or x \geq 5

+1

Interval Notation

(- \infty, - 3] \cup [5, \infty)

Solution steps

3 ∣ x - 1 ∣ \geq 12

Divide both sides by

3

∣ x - 1 ∣ \geq 4

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

x - 1 \leq - 4 or x - 1 \geq 4

x - 1 \leq - 4 or x - 1 \geq 4

x \leq - 3 or x \geq 5

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Frequently Asked Questions (FAQ)

What is 3|x-1|>= 12 ?
The solution to 3|x-1|>= 12 is x<=-3\lor x>= 5