What is -5<= (2(x+3))/7 <= 5 ?

The solution to -5<= (2(x+3))/7 <= 5 is -41/2 <= x<= 29/2

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-5<= (2(x+3))/7 <= 5

- 5 \leq \frac{2 ( x + 3 )}{7} \leq 5

- \frac{41}{2} \leq x \leq \frac{29}{2}

Interval Notation

[- \frac{41}{2}, \frac{29}{2}]

Decimal Notation

- 20.5 \leq x \leq 14.5

Solution steps

- 5 \leq \frac{2 ( x + 3 )}{7} \leq 5

a \leq u \leq b

then

a \leq u and u \leq b

- 5 \leq \frac{2 ( x + 3 )}{7} and \frac{2 ( x + 3 )}{7} \leq 5

- 5 \leq \frac{2 ( x + 3 )}{7} : x \geq - \frac{41}{2}

\frac{2 ( x + 3 )}{7} \leq 5 : x \leq \frac{29}{2}

Combine the intervals

x \geq - \frac{41}{2} and x \leq \frac{29}{2}

Merge Overlapping Intervals

- \frac{41}{2} \leq x \leq \frac{29}{2}

7 k = 3 k - 36

x^{\frac{2}{3}}

15 n^{2} - 22 n + 8 = 0

2 x^{2} + 7 x - 5 = 0

What is -5<= (2(x+3))/7 <= 5 ?
The solution to -5<= (2(x+3))/7 <= 5 is -41/2 <= x<= 29/2