What are the solutions to the equation x^2-11x+6=0 ?

The solutions to the equation x^2-11x+6=0 are x=(11+sqrt(97))/2 ,x=(11-sqrt(97))/2

Find the zeros of x^2-11x+6=0

The zeros of x^2-11x+6=0 are x=(11+sqrt(97))/2 ,x=(11-sqrt(97))/2

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x^{2} - 11 x + 6 = 0

x = \frac{11 + 97}{2}, x = \frac{11 - 97}{2}

Decimal Notation

x = 10.42442 \dots, x = 0.57557 \dots

Solution steps

x^{2} - 11 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 6 = 97

x_{1, 2} = \frac{- ( - 11 ) \pm 97}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 97}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 97}{2 \cdot 1}

x = \frac{- ( - 11 ) + 97}{2 \cdot 1} : \frac{11 + 97}{2}

x = \frac{- ( - 11 ) - 97}{2 \cdot 1} : \frac{11 - 97}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 97}{2}, x = \frac{11 - 97}{2}

1 x = - 1

0.5 x + \frac{4}{3} x = x + 10

8 x^{2} + x - 75 = 0

\frac{x}{9} - \frac{x - y}{6}

x = (x - 2)^{2}

What are the solutions to the equation x^2-11x+6=0 ?
The solutions to the equation x^2-11x+6=0 are x=(11+sqrt(97))/2 ,x=(11-sqrt(97))/2
Find the zeros of x^2-11x+6=0
The zeros of x^2-11x+6=0 are x=(11+sqrt(97))/2 ,x=(11-sqrt(97))/2