What are the solutions to the equation x^2+3-x=16 ?

The solutions to the equation x^2+3-x=16 are x=(1+sqrt(53))/2 ,x=(1-sqrt(53))/2

Find the zeros of x^2+3-x=16

The zeros of x^2+3-x=16 are x=(1+sqrt(53))/2 ,x=(1-sqrt(53))/2

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x^{2} + 3 - x = 16

x = \frac{1 + 53}{2}, x = \frac{1 - 53}{2}

Decimal Notation

x = 4.14005 \dots, x = - 3.14005 \dots

Solution steps

x^{2} + 3 - x = 16

Move

16

to the left side

x^{2} - x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 13) = 53

x_{1, 2} = \frac{- ( - 1 ) \pm 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 53}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 53}{2 \cdot 1}

x = \frac{- ( - 1 ) + 53}{2 \cdot 1} : \frac{1 + 53}{2}

x = \frac{- ( - 1 ) - 53}{2 \cdot 1} : \frac{1 - 53}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 53}{2}, x = \frac{1 - 53}{2}

4 x - 2 x^{2}

∣ n ∣ = 12

\frac{x}{3} - \frac{3}{4} = \frac{3 x + 12}{12}

75 a^{2} - 15

0 = x^{2} - 7 x + 9

What are the solutions to the equation x^2+3-x=16 ?
The solutions to the equation x^2+3-x=16 are x=(1+sqrt(53))/2 ,x=(1-sqrt(53))/2
Find the zeros of x^2+3-x=16
The zeros of x^2+3-x=16 are x=(1+sqrt(53))/2 ,x=(1-sqrt(53))/2