What is (12q^{-3})/((3p^4q^{-3))^{-4}} ?

The solution to (12q^{-3})/((3p^4q^{-3))^{-4}} is (972p^{16})/(q^{15)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (12q^{-3})/((3p^4q^{-3))^{-4}}

simplify

\frac{12 q ^{- 3}}{( 3 p ^{4} q ^{- 3} ) ^{- 4}}

\frac{972 p ^{16}}{q ^{15}}

Solution steps

\frac{12 q ^{- 3}}{( 3 p ^{4} q ^{- 3} ) ^{- 4}}

Simplify

(3 p^{4} q^{- 3})^{- 4} : 3^{- 4} \cdot \frac{1}{p ^{16}} q^{12}

= \frac{12 q ^{- 3}}{3 ^{- 4} \cdot \frac{1}{p ^{16}} q ^{12}}

Factor the number:

12 = 3 \cdot 4

= \frac{3 \cdot 4 q ^{- 3}}{3 ^{- 4} \cdot \frac{1}{p ^{16}} q ^{12}}

\frac{3}{3 ^{- 4}} = 3^{5}

= \frac{3 ^{5} \cdot 4 q ^{- 3}}{\frac{1}{p ^{16}} q ^{12}}

Simplify

\frac{q ^{- 3}}{q ^{12}} : \frac{1}{q ^{15}}

= \frac{3 ^{5} \cdot 4}{\frac{1}{p ^{16}} q ^{15}}

Simplify

\frac{3 ^{5} \cdot 4}{\frac{1}{p ^{16}} q ^{15}} : \frac{972 p ^{16}}{q ^{15}}

= \frac{972 p ^{16}}{q ^{15}}

3 x^{2} - x - 2

6 x^{2} + 7 x - 20 = 0

\frac{3}{8} + \frac{1}{4}

x^{2} - 24 x + 80 = 0

3 (3 x + 1) = 9 - 5 (3 x - 3)

What is (12q^{-3})/((3p^4q^{-3))^{-4}} ?
The solution to (12q^{-3})/((3p^4q^{-3))^{-4}} is (972p^{16})/(q^{15)}