What are the solutions to the equation 6x^2+7x-20=0 ?

The solutions to the equation 6x^2+7x-20=0 are x= 4/3 ,x=-5/2

Find the zeros of 6x^2+7x-20=0

The zeros of 6x^2+7x-20=0 are x= 4/3 ,x=-5/2

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6 x^{2} + 7 x - 20 = 0

x = \frac{4}{3}, x = - \frac{5}{2}

Solution steps

6 x^{2} + 7 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 ( - 20 )}{2 \cdot 6}

7^{2} - 4 \cdot 6 (- 20) = 23

x_{1, 2} = \frac{- 7 \pm 23}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 23}{2 \cdot 6}, x_{2} = \frac{- 7 - 23}{2 \cdot 6}

x = \frac{- 7 + 23}{2 \cdot 6} : \frac{4}{3}

x = \frac{- 7 - 23}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{5}{2}

\frac{3}{8} + \frac{1}{4}

x^{2} - 24 x + 80 = 0

3 (3 x + 1) = 9 - 5 (3 x - 3)

∣ v + 4 ∣ \geq 4

lo g_{2} (3 x + 1) \leq 4

What are the solutions to the equation 6x^2+7x-20=0 ?
The solutions to the equation 6x^2+7x-20=0 are x= 4/3 ,x=-5/2
Find the zeros of 6x^2+7x-20=0
The zeros of 6x^2+7x-20=0 are x= 4/3 ,x=-5/2