What are the solutions to the equation -2x^2-6x+5=0 ?

The solutions to the equation -2x^2-6x+5=0 are x=-(3+sqrt(19))/2 ,x=(sqrt(19)-3)/2

Find the zeros of -2x^2-6x+5=0

The zeros of -2x^2-6x+5=0 are x=-(3+sqrt(19))/2 ,x=(sqrt(19)-3)/2

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- 2 x^{2} - 6 x + 5 = 0

x = - \frac{3 + 19}{2}, x = \frac{19 - 3}{2}

Decimal Notation

x = - 3.67944 \dots, x = 0.67944 \dots

Solution steps

- 2 x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

(- 6)^{2} - 4 (- 2) \cdot 5 = 219

x_{1, 2} = \frac{- ( - 6 ) \pm 2 19}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 19}{2 ( - 2 )}, x_{2} = \frac{- ( - 6 ) - 2 19}{2 ( - 2 )}

x = \frac{- ( - 6 ) + 2 19}{2 ( - 2 )} : - \frac{3 + 19}{2}

x = \frac{- ( - 6 ) - 2 19}{2 ( - 2 )} : \frac{19 - 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 19}{2}, x = \frac{19 - 3}{2}

2 x + 5 \geq - 1

5 \cdot 1 0^{2}

- 5 (p + 53) = - 4

3 x^{2} - 25 = 0

2 x^{2} - 11 x - 16 \leq 5

What are the solutions to the equation -2x^2-6x+5=0 ?
The solutions to the equation -2x^2-6x+5=0 are x=-(3+sqrt(19))/2 ,x=(sqrt(19)-3)/2
Find the zeros of -2x^2-6x+5=0
The zeros of -2x^2-6x+5=0 are x=-(3+sqrt(19))/2 ,x=(sqrt(19)-3)/2