What are the solutions to the equation m^2+10m+24=0 ?

The solutions to the equation m^2+10m+24=0 are m=-4,m=-6

Find the zeros of m^2+10m+24=0

The zeros of m^2+10m+24=0 are m=-4,m=-6

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m^{2} + 10 m + 24 = 0

m = - 4, m = - 6

Solution steps

m^{2} + 10 m + 24 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

m_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 10 + 2}{2 \cdot 1}, m_{2} = \frac{- 10 - 2}{2 \cdot 1}

m = \frac{- 10 + 2}{2 \cdot 1} : - 4

m = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

m = - 4, m = - 6

s^{2} - 100 = 0

49 x^{4} - 64

\frac{12 !}{2 ! ( 12 - 2 ) !}

10 x^{2} + 6 x + 1 = 0

- 4 m + 21 (m - 1) \leq 15 m + 2 (m - 1)

What are the solutions to the equation m^2+10m+24=0 ?
The solutions to the equation m^2+10m+24=0 are m=-4,m=-6
Find the zeros of m^2+10m+24=0
The zeros of m^2+10m+24=0 are m=-4,m=-6