What are the solutions to the equation 6x^2+78x+240=0 ?

The solutions to the equation 6x^2+78x+240=0 are x=-5,x=-8

Find the zeros of 6x^2+78x+240=0

The zeros of 6x^2+78x+240=0 are x=-5,x=-8

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6 x^{2} + 78 x + 240 = 0

x = - 5, x = - 8

Solution steps

6 x^{2} + 78 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 78 \pm 7 8 ^{2} - 4 \cdot 6 \cdot 240}{2 \cdot 6}

7 8^{2} - 4 \cdot 6 \cdot 240 = 18

x_{1, 2} = \frac{- 78 \pm 18}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 78 + 18}{2 \cdot 6}, x_{2} = \frac{- 78 - 18}{2 \cdot 6}

x = \frac{- 78 + 18}{2 \cdot 6} : - 5

x = \frac{- 78 - 18}{2 \cdot 6} : - 8

The solutions to the quadratic equation are:

x = - 5, x = - 8

X + 1 = 2

x^{2} - 9 x + 9 = 0

32 \cdot 5

2 (x - 1)^{2} - 5 = 3

4 x^{2} - (2 x + 3)^{2}

What are the solutions to the equation 6x^2+78x+240=0 ?
The solutions to the equation 6x^2+78x+240=0 are x=-5,x=-8
Find the zeros of 6x^2+78x+240=0
The zeros of 6x^2+78x+240=0 are x=-5,x=-8