What are the solutions to the equation 2(x-1)^2-5=3 ?

The solutions to the equation 2(x-1)^2-5=3 are x=3,x=-1

Find the zeros of 2(x-1)^2-5=3

The zeros of 2(x-1)^2-5=3 are x=3,x=-1

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2 (x - 1)^{2} - 5 = 3

x = 3, x = - 1

Solution steps

2 (x - 1)^{2} - 5 = 3

Move

5

to the right side

2 (x - 1)^{2} = 8

Divide both sides by

2

(x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 4 : x = 3

Solve

x - 1 = - 4 : x = - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

4 x^{2} - (2 x + 3)^{2}

(\frac{5 ^{3}}{5 ^{4}})^{- 3}

x^{2} - 9 = (x + 3) (x - 3)

x^{3} - 2 x^{2} - 3 x

3 x^{2} + x + 1 = 0

What are the solutions to the equation 2(x-1)^2-5=3 ?
The solutions to the equation 2(x-1)^2-5=3 are x=3,x=-1
Find the zeros of 2(x-1)^2-5=3
The zeros of 2(x-1)^2-5=3 are x=3,x=-1