What are the solutions to the equation -3p^2+17p=20 ?

The solutions to the equation -3p^2+17p=20 are p= 5/3 ,p=4

Find the zeros of -3p^2+17p=20

The zeros of -3p^2+17p=20 are p= 5/3 ,p=4

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- 3 p^{2} + 17 p = 20

p = \frac{5}{3}, p = 4

Decimal Notation

p = 1.66666 \dots, p = 4

Solution steps

- 3 p^{2} + 17 p = 20

Move

20

to the left side

- 3 p^{2} + 17 p - 20 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 3 ) ( - 20 )}{2 ( - 3 )}

1 7^{2} - 4 (- 3) (- 20) = 7

p_{1, 2} = \frac{- 17 \pm 7}{2 ( - 3 )}

Separate the solutions

p_{1} = \frac{- 17 + 7}{2 ( - 3 )}, p_{2} = \frac{- 17 - 7}{2 ( - 3 )}

p = \frac{- 17 + 7}{2 ( - 3 )} : \frac{5}{3}

p = \frac{- 17 - 7}{2 ( - 3 )} : 4

The solutions to the quadratic equation are:

p = \frac{5}{3}, p = 4

\frac{( 1 - 3 i ) ^{2}}{i - 1}

3 2^{- \frac{3}{5}}

(4 x + 5)^{2} = 5 x^{2} + 4 x

lo g_{3} (x) = 2

32 - \frac{64}{3} + \frac{32}{5}

What are the solutions to the equation -3p^2+17p=20 ?
The solutions to the equation -3p^2+17p=20 are p= 5/3 ,p=4
Find the zeros of -3p^2+17p=20
The zeros of -3p^2+17p=20 are p= 5/3 ,p=4