What is (10x^4)/(6y^5)*(5y^2)/(5x^2) ?

The solution to (10x^4)/(6y^5)*(5y^2)/(5x^2) is (5x^2)/(3y^3)

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simplify (10x^4)/(6y^5)*(5y^2)/(5x^2)

simplify

\frac{10 x ^{4}}{6 y ^{5}} \cdot \frac{5 y ^{2}}{5 x ^{2}}

\frac{5 x ^{2}}{3 y ^{3}}

Solution steps

\frac{10 x ^{4}}{6 y ^{5}} \cdot \frac{5 y ^{2}}{5 x ^{2}}

Cancel

\frac{10 x ^{4}}{6 y ^{5}} : \frac{5 x ^{4}}{3 y ^{5}}

= \frac{5 x ^{4}}{3 y ^{5}} \cdot \frac{5 y ^{2}}{5 x ^{2}}

Cancel the common factor:

5

= \frac{5 x ^{4}}{3 y ^{5}} \cdot \frac{y ^{2}}{x ^{2}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 x ^{4} y ^{2}}{3 y ^{5} x ^{2}}

Simplify

\frac{x ^{4}}{x ^{2}} : x^{2}

= \frac{5 x ^{2} y ^{2}}{3 y ^{5}}

Simplify

\frac{y ^{2}}{y ^{5}} : \frac{1}{y ^{3}}

= \frac{5 x ^{2}}{3 y ^{3}}

\frac{6 x + 1}{11} = \frac{2 x - 3}{7}

4 x^{2} + 26 x + 30

x^{3} - 5 x^{2} + 3 x + 9

(8 d)^{\frac{2}{3}}

- 6 \geq 4 - 5 x^{3}

What is (10x^4)/(6y^5)*(5y^2)/(5x^2) ?
The solution to (10x^4)/(6y^5)*(5y^2)/(5x^2) is (5x^2)/(3y^3)