What are the solutions to the equation 2k^2+22k=74 ?

The solutions to the equation 2k^2+22k=74 are k=(-11+sqrt(269))/2 ,k=-(11+sqrt(269))/2

Find the zeros of 2k^2+22k=74

The zeros of 2k^2+22k=74 are k=(-11+sqrt(269))/2 ,k=-(11+sqrt(269))/2

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2 k^{2} + 22 k = 74

k = \frac{- 11 + 269}{2}, k = - \frac{11 + 269}{2}

Solution steps

2 k^{2} + 22 k = 74

Move

74

to the left side

2 k^{2} + 22 k - 74 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 2 ( - 74 )}{2 \cdot 2}

2 2^{2} - 4 \cdot 2 (- 74) = 2269

k_{1, 2} = \frac{- 22 \pm 2 269}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 22 + 2 269}{2 \cdot 2}, k_{2} = \frac{- 22 - 2 269}{2 \cdot 2}

k = \frac{- 22 + 2 269}{2 \cdot 2} : \frac{- 11 + 269}{2}

k = \frac{- 22 - 2 269}{2 \cdot 2} : - \frac{11 + 269}{2}

The solutions to the quadratic equation are:

k = \frac{- 11 + 269}{2}, k = - \frac{11 + 269}{2}

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What are the solutions to the equation 2k^2+22k=74 ?
The solutions to the equation 2k^2+22k=74 are k=(-11+sqrt(269))/2 ,k=-(11+sqrt(269))/2
Find the zeros of 2k^2+22k=74
The zeros of 2k^2+22k=74 are k=(-11+sqrt(269))/2 ,k=-(11+sqrt(269))/2