What are the solutions to the equation 5+2x+x^2=0 ?

The solutions to the equation 5+2x+x^2=0 are x=-1+2i,x=-1-2i

Find the zeros of 5+2x+x^2=0

The zeros of 5+2x+x^2=0 are x=-1+2i,x=-1-2i

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5 + 2 x + x^{2} = 0

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

5 + 2 x + x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

x_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

x = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

x = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

\frac{3 m}{6 m}

4 x - 13 \leq 7

16 x^{2} - 112

5 v^{2} - 15 v + 12 = 3 v

30 > x + 10 > 20

What are the solutions to the equation 5+2x+x^2=0 ?
The solutions to the equation 5+2x+x^2=0 are x=-1+2i,x=-1-2i
Find the zeros of 5+2x+x^2=0
The zeros of 5+2x+x^2=0 are x=-1+2i,x=-1-2i