What are the solutions to the equation x^2+20x+36=0 ?

The solutions to the equation x^2+20x+36=0 are x=-2,x=-18

Find the zeros of x^2+20x+36=0

The zeros of x^2+20x+36=0 are x=-2,x=-18

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x^{2} + 20 x + 36 = 0

x = - 2, x = - 18

Solution steps

x^{2} + 20 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 36 = 16

x_{1, 2} = \frac{- 20 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 16}{2 \cdot 1}, x_{2} = \frac{- 20 - 16}{2 \cdot 1}

x = \frac{- 20 + 16}{2 \cdot 1} : - 2

x = \frac{- 20 - 16}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = - 2, x = - 18

3 (x + 10)^{2} + 13 = 40

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N a O H + H Cl

- 10 > - 8 + y

\frac{2}{2}

What are the solutions to the equation x^2+20x+36=0 ?
The solutions to the equation x^2+20x+36=0 are x=-2,x=-18
Find the zeros of x^2+20x+36=0
The zeros of x^2+20x+36=0 are x=-2,x=-18