What are the solutions to the equation 16x^2+18=19 ?

The solutions to the equation 16x^2+18=19 are x= 1/4 ,x=-1/4

Find the zeros of 16x^2+18=19

The zeros of 16x^2+18=19 are x= 1/4 ,x=-1/4

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16 x^{2} + 18 = 19

x = \frac{1}{4}, x = - \frac{1}{4}

Solution steps

16 x^{2} + 18 = 19

Move

18

to the right side

16 x^{2} = 1

Divide both sides by

16

x^{2} = \frac{1}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{16}, x = - \frac{1}{16}

\frac{1}{16} = \frac{1}{4}

- \frac{1}{16} = - \frac{1}{4}

x = \frac{1}{4}, x = - \frac{1}{4}

y \cdot y^{2}

\frac{3 x + 6}{x - 1} < 2

- \frac{54}{3}

4 x^{2} - 3 x - 8 = 0

16 w^{2} + 24 w + 9

What are the solutions to the equation 16x^2+18=19 ?
The solutions to the equation 16x^2+18=19 are x= 1/4 ,x=-1/4
Find the zeros of 16x^2+18=19
The zeros of 16x^2+18=19 are x= 1/4 ,x=-1/4