What are the solutions to the equation -2(x+4)^2-9=-297 ?

The solutions to the equation -2(x+4)^2-9=-297 are x=8,x=-16

Find the zeros of -2(x+4)^2-9=-297

The zeros of -2(x+4)^2-9=-297 are x=8,x=-16

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- 2 (x + 4)^{2} - 9 = - 297

x = 8, x = - 16

Solution steps

- 2 (x + 4)^{2} - 9 = - 297

Move

9

to the right side

- 2 (x + 4)^{2} = - 288

Divide both sides by

- 2

(x + 4)^{2} = 144

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 144 : x = 8

Solve

x + 4 = - 144 : x = - 16

The solutions to the quadratic equation are:

x = 8, x = - 16

x^{2} + x y^{2} + 2 x yz + x y^{2} + y^{3} + 2 y^{2} z

x^{2} = - 10

x^{2} + 7 x + 6 x + 42

\frac{2 x + 1}{x + 1} \leq x

u^{2} - 8 u + 16

What are the solutions to the equation -2(x+4)^2-9=-297 ?
The solutions to the equation -2(x+4)^2-9=-297 are x=8,x=-16
Find the zeros of -2(x+4)^2-9=-297
The zeros of -2(x+4)^2-9=-297 are x=8,x=-16