What are the solutions to the equation 3x^2-2x+8=0 ?

The solutions to the equation 3x^2-2x+8=0 are x= 1/3+i(sqrt(23))/3 ,x= 1/3-i(sqrt(23))/3

Find the zeros of 3x^2-2x+8=0

The zeros of 3x^2-2x+8=0 are x= 1/3+i(sqrt(23))/3 ,x= 1/3-i(sqrt(23))/3

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3 x^{2} - 2 x + 8 = 0

x = \frac{1}{3} + i \frac{23}{3}, x = \frac{1}{3} - i \frac{23}{3}

Solution steps

3 x^{2} - 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 8 : 223 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 23 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 23 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 23 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 23 i}{2 \cdot 3} : \frac{1}{3} + i \frac{23}{3}

x = \frac{- ( - 2 ) - 2 23 i}{2 \cdot 3} : \frac{1}{3} - i \frac{23}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{23}{3}, x = \frac{1}{3} - i \frac{23}{3}

164883 (1 + \frac{45.26}{9.8})

\frac{1}{4} - \frac{1}{8}

0 = x^{2} + 6 x + 13

c^{2} - 9 c - 10

\frac{1 0 ^{2}}{2 ^{10}}

What are the solutions to the equation 3x^2-2x+8=0 ?
The solutions to the equation 3x^2-2x+8=0 are x= 1/3+i(sqrt(23))/3 ,x= 1/3-i(sqrt(23))/3
Find the zeros of 3x^2-2x+8=0
The zeros of 3x^2-2x+8=0 are x= 1/3+i(sqrt(23))/3 ,x= 1/3-i(sqrt(23))/3