What are the solutions to the equation 0=x^2+6x+13 ?

The solutions to the equation 0=x^2+6x+13 are x=-3+2i,x=-3-2i

Find the zeros of 0=x^2+6x+13

The zeros of 0=x^2+6x+13 are x=-3+2i,x=-3-2i

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0 = x^{2} + 6 x + 13

x = - 3 + 2 i, x = - 3 - 2 i

Solution steps

0 = x^{2} + 6 x + 13

Switch sides

x^{2} + 6 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 13 : 4 i

x_{1, 2} = \frac{- 6 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 i}{2 \cdot 1}

x = \frac{- 6 + 4 i}{2 \cdot 1} : - 3 + 2 i

x = \frac{- 6 - 4 i}{2 \cdot 1} : - 3 - 2 i

The solutions to the quadratic equation are:

x = - 3 + 2 i, x = - 3 - 2 i

c^{2} - 9 c - 10

\frac{1 0 ^{2}}{2 ^{10}}

- 2 x^{2} + 5 x - 18 = 7

x^{3} - 12 x^{2} + 44 x - 48

\frac{n}{1.6} = 5

What are the solutions to the equation 0=x^2+6x+13 ?
The solutions to the equation 0=x^2+6x+13 are x=-3+2i,x=-3-2i
Find the zeros of 0=x^2+6x+13
The zeros of 0=x^2+6x+13 are x=-3+2i,x=-3-2i