What are the solutions to the equation -2x^2+5x-18=7 ?

The solutions to the equation -2x^2+5x-18=7 are x= 5/4-i(5sqrt(7))/4 ,x= 5/4+i(5sqrt(7))/4

Find the zeros of -2x^2+5x-18=7

The zeros of -2x^2+5x-18=7 are x= 5/4-i(5sqrt(7))/4 ,x= 5/4+i(5sqrt(7))/4

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- 2 x^{2} + 5 x - 18 = 7

x = \frac{5}{4} - i \frac{5 7}{4}, x = \frac{5}{4} + i \frac{5 7}{4}

Solution steps

- 2 x^{2} + 5 x - 18 = 7

Move

7

to the left side

- 2 x^{2} + 5 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) ( - 25 )}{2 ( - 2 )}

Simplify

5^{2} - 4 (- 2) (- 25) : 57 i

x_{1, 2} = \frac{- 5 \pm 5 7 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 5 7 i}{2 ( - 2 )}, x_{2} = \frac{- 5 - 5 7 i}{2 ( - 2 )}

x = \frac{- 5 + 5 7 i}{2 ( - 2 )} : \frac{5}{4} - i \frac{5 7}{4}

x = \frac{- 5 - 5 7 i}{2 ( - 2 )} : \frac{5}{4} + i \frac{5 7}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4} - i \frac{5 7}{4}, x = \frac{5}{4} + i \frac{5 7}{4}

x^{3} - 12 x^{2} + 44 x - 48

\frac{n}{1.6} = 5

v^{2} - 12 v + 36

x^{2} + 14 x = - 130

75 - 19 x = 11 (x + 15)

What are the solutions to the equation -2x^2+5x-18=7 ?
The solutions to the equation -2x^2+5x-18=7 are x= 5/4-i(5sqrt(7))/4 ,x= 5/4+i(5sqrt(7))/4
Find the zeros of -2x^2+5x-18=7
The zeros of -2x^2+5x-18=7 are x= 5/4-i(5sqrt(7))/4 ,x= 5/4+i(5sqrt(7))/4