What are the solutions to the equation 5(x^2+1)-7=3 ?

The solutions to the equation 5(x^2+1)-7=3 are x=1,x=-1

Find the zeros of 5(x^2+1)-7=3

The zeros of 5(x^2+1)-7=3 are x=1,x=-1

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5 (x^{2} + 1) - 7 = 3

x = 1, x = - 1

Solution steps

5 (x^{2} + 1) - 7 = 3

Move

7

to the right side

5 (x^{2} + 1) = 10

Divide both sides by

5

x^{2} + 1 = 2

Move

1

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

∣ 8 x ∣ + 4 = 10

\frac{8}{9}

0 = x^{2} - 6 x + 13

(1 + \frac{3 i}{n})^{2}

8 y^{3} - 2 y^{4}

What are the solutions to the equation 5(x^2+1)-7=3 ?
The solutions to the equation 5(x^2+1)-7=3 are x=1,x=-1
Find the zeros of 5(x^2+1)-7=3
The zeros of 5(x^2+1)-7=3 are x=1,x=-1