What is the answer to sqrt(8-(-1))=2(-1)+d ?

The answer to sqrt(8-(-1))=2(-1)+d is d=5

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sqrt(8-(-1))=2(-1)+d

8 - (- 1) = 2 (- 1) + d

d = 5

Solution steps

8 - (- 1) = 2 (- 1) + d

Switch sides

2 (- 1) + d = 8 - (- 1)

Remove parentheses:

(- a) = - a

- 2 \cdot 1 + d = 8 - (- 1)

Multiply the numbers:

2 \cdot 1 = 2

- 2 + d = 8 - (- 1)

Apply rule

- (- a) = a

- 2 + d = 8 + 1

Add the numbers:

8 + 1 = 9

- 2 + d = 9

Factor the number:

9 = 3^{2}

- 2 + d = 3^{2}

Apply radical rule:

3^{2} = 3

- 2 + d = 3

Move

2

to the right side

d = 5

x + 2 = x + 2

164

2 x^{4} + 13 x^{3} + 11 x^{2} + 117 x - 63

7 (x + 3) - 8 x \leq 3 (3 x + 1) - 7 x

x^{2} - 2 x - 99 = 0

What is the answer to sqrt(8-(-1))=2(-1)+d ?
The answer to sqrt(8-(-1))=2(-1)+d is d=5
Solve for d: sqrt(8-(-1))=2(-1)+d
The solution is d=5