What are the solutions to the equation 2x^2+12x=66 ?

The solutions to the equation 2x^2+12x=66 are x=-3+sqrt(42),x=-3-sqrt(42)

Find the zeros of 2x^2+12x=66

The zeros of 2x^2+12x=66 are x=-3+sqrt(42),x=-3-sqrt(42)

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2 x^{2} + 12 x = 66

x = - 3 + 42, x = - 3 - 42

Solution steps

2 x^{2} + 12 x = 66

Move

66

to the left side

2 x^{2} + 12 x - 66 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 66 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 66) = 442

x_{1, 2} = \frac{- 12 \pm 4 42}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 42}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 42}{2 \cdot 2}

x = \frac{- 12 + 4 42}{2 \cdot 2} : - 3 + 42

x = \frac{- 12 - 4 42}{2 \cdot 2} : - 3 - 42

The solutions to the quadratic equation are:

x = - 3 + 42, x = - 3 - 42

4 - y^{2} = 0

3 x + 1 > 2 x - 5 > x - 7

- 9 - 3 n = - 3 (- 3 n - 5)

- m (2 + m) = 8

3 v + 3 = 9

What are the solutions to the equation 2x^2+12x=66 ?
The solutions to the equation 2x^2+12x=66 are x=-3+sqrt(42),x=-3-sqrt(42)
Find the zeros of 2x^2+12x=66
The zeros of 2x^2+12x=66 are x=-3+sqrt(42),x=-3-sqrt(42)