What is -(33}{x+3}>=-\frac{16)/x-1 ?

The solution to -(33}{x+3}>=-\frac{16)/x-1 is x = 8

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-(33}{x+3}>=-\frac{16)/x-1

- \frac{33}{x + 3} \geq - \frac{16}{x} - 1

x < - 3 or 0 < x \leq 6 or x \geq 8

Solution steps

- \frac{33}{x + 3} \geq - \frac{16}{x} - 1

Rewrite in standard form

\frac{x ^{2} - 14 x + 48}{x ( x + 3 )} \geq 0

Factor

\frac{x ^{2} - 14 x + 48}{x ( x + 3 )} : \frac{( x - 6 ) ( x - 8 )}{x ( x + 3 )}

\frac{( x - 6 ) ( x - 8 )}{x ( x + 3 )} \geq 0

Identify the intervals

x < - 3 or 0 < x \leq 6 or x \geq 8

3 x^{2} + 23 x - 8 = 0

125 - 8 y^{3}

x^{3} + 6 x^{2} + 9 x + 2

1 + \frac{0.05}{4}

\frac{7}{\frac{6}{4}}

What is -(33}{x+3}>=-\frac{16)/x-1 ?
The solution to -(33}{x+3}>=-\frac{16)/x-1 is x<-3\lor 0<x<= 6\lor x>= 8