What is (15a^6bc^4)/(35a^2c^4) ?

The solution to (15a^6bc^4)/(35a^2c^4) is (3a^4b)/7

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simplify (15a^6bc^4)/(35a^2c^4)

simplify

\frac{15 a ^{6} b c ^{4}}{35 a ^{2} c ^{4}}

\frac{3 a ^{4} b}{7}

Solution steps

\frac{15 a ^{6} b c ^{4}}{35 a ^{2} c ^{4}}

Cancel the common factor:

c^{4}

= \frac{15 a ^{6} b}{35 a ^{2}}

Factor the number:

15 = 5 \cdot 3

= \frac{5 \cdot 3 a ^{6} b}{35 a ^{2}}

Factor the number:

35 = 5 \cdot 7

= \frac{5 \cdot 3 a ^{6} b}{5 \cdot 7 a ^{2}}

Cancel the common factor:

5

= \frac{3 a ^{6} b}{7 a ^{2}}

Simplify

\frac{a ^{6}}{a ^{2}} : a^{4}

= \frac{3 a ^{4} b}{7}

\frac{2 2}{3} x - 3 \leq \frac{4 3}{2}

- 3 x^{2} + 4 x - 0.25 = 0

12 = x (240)^{2}

20 a - 21 = 18

e^{0.69314}

What is (15a^6bc^4)/(35a^2c^4) ?
The solution to (15a^6bc^4)/(35a^2c^4) is (3a^4b)/7