What are the solutions to the equation u^2-10u+24=0 ?

The solutions to the equation u^2-10u+24=0 are u=6,u=4

Find the zeros of u^2-10u+24=0

The zeros of u^2-10u+24=0 are u=6,u=4

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u^{2} - 10 u + 24 = 0

u = 6, u = 4

Solution steps

u^{2} - 10 u + 24 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

u_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, u_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

u = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

u = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

u = 6, u = 4

x^{4} y - x^{5} y^{4}

(0 - 4)^{2} + (y + 2)^{2} = 25

30 (25 - t^{2}) = 400

(x - 8) (x - 3) (x + 2) > 0

3 - \frac{1}{2} x > 1

What are the solutions to the equation u^2-10u+24=0 ?
The solutions to the equation u^2-10u+24=0 are u=6,u=4
Find the zeros of u^2-10u+24=0
The zeros of u^2-10u+24=0 are u=6,u=4