What are the solutions to the equation 30(25-t^2)=400 ?

The solutions to the equation 30(25-t^2)=400 are t=sqrt(35/3),t=-sqrt(35/3)

Find the zeros of 30(25-t^2)=400

The zeros of 30(25-t^2)=400 are t=sqrt(35/3),t=-sqrt(35/3)

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30 (25 - t^{2}) = 400

t = \frac{35}{3}, t = - \frac{35}{3}

Solution steps

30 (25 - t^{2}) = 400

Divide both sides by

30

25 - t^{2} = \frac{40}{3}

Move

25

to the right side

- t^{2} = - \frac{35}{3}

Divide both sides by

- 1

t^{2} = \frac{35}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{35}{3}, t = - \frac{35}{3}

(x - 8) (x - 3) (x + 2) > 0

3 - \frac{1}{2} x > 1

2 y^{2} - 6 y - 8 = 0

- 3 = \frac{h + 8}{2}

\frac{1}{4} + \frac{3}{4}

What are the solutions to the equation 30(25-t^2)=400 ?
The solutions to the equation 30(25-t^2)=400 are t=sqrt(35/3),t=-sqrt(35/3)
Find the zeros of 30(25-t^2)=400
The zeros of 30(25-t^2)=400 are t=sqrt(35/3),t=-sqrt(35/3)