What are the solutions to the equation 2y^2-6y-8=0 ?

The solutions to the equation 2y^2-6y-8=0 are y=4,y=-1

Find the zeros of 2y^2-6y-8=0

The zeros of 2y^2-6y-8=0 are y=4,y=-1

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2 y^{2} - 6 y - 8 = 0

y = 4, y = - 1

Solution steps

2 y^{2} - 6 y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 8) = 10

y_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 2}, y_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 2}

y = \frac{- ( - 6 ) + 10}{2 \cdot 2} : 4

y = \frac{- ( - 6 ) - 10}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

y = 4, y = - 1

- 3 = \frac{h + 8}{2}

\frac{1}{4} + \frac{3}{4}

x^{2} > x + 20

\frac{( 10 \cdot 1 0 ^{9} ) \cdot 2.5}{( 3 \cdot 1 0 ^{9} )}

k^{2} - 13 k + 40 = 0

What are the solutions to the equation 2y^2-6y-8=0 ?
The solutions to the equation 2y^2-6y-8=0 are y=4,y=-1
Find the zeros of 2y^2-6y-8=0
The zeros of 2y^2-6y-8=0 are y=4,y=-1