What are the solutions to the equation 2x^2-12x-14=x^2-8x ?

The solutions to the equation 2x^2-12x-14=x^2-8x are x=2+3sqrt(2),x=2-3sqrt(2)

Find the zeros of 2x^2-12x-14=x^2-8x

The zeros of 2x^2-12x-14=x^2-8x are x=2+3sqrt(2),x=2-3sqrt(2)

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2 x^{2} - 12 x - 14 = x^{2} - 8 x

x = 2 + 32, x = 2 - 32

Solution steps

2 x^{2} - 12 x - 14 = x^{2} - 8 x

Move

8 x

to the left side

2 x^{2} - 4 x - 14 = x^{2}

Move

x^{2}

to the left side

x^{2} - 4 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 14) = 62

x_{1, 2} = \frac{- ( - 4 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6 2}{2 \cdot 1} : 2 + 32

x = \frac{- ( - 4 ) - 6 2}{2 \cdot 1} : 2 - 32

The solutions to the quadratic equation are:

x = 2 + 32, x = 2 - 32

(x + 4) (x - 15) = 6 x

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49 x^{8} y z^{4} + 28 x^{4} y^{4} z^{3}

x + 3 = x^{2} + 5 x + 6

x^{2} y^{2} - 9 y^{2} - 4 x^{2} + 36

What are the solutions to the equation 2x^2-12x-14=x^2-8x ?
The solutions to the equation 2x^2-12x-14=x^2-8x are x=2+3sqrt(2),x=2-3sqrt(2)
Find the zeros of 2x^2-12x-14=x^2-8x
The zeros of 2x^2-12x-14=x^2-8x are x=2+3sqrt(2),x=2-3sqrt(2)