What are the solutions to the equation 2x^2=8x ?

The solutions to the equation 2x^2=8x are x=0,x=4

Find the zeros of 2x^2=8x

The zeros of 2x^2=8x are x=0,x=4

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2 x^{2} = 8 x

x = 0, x = 4

Solution steps

2 x^{2} = 8 x

Move

8 x

to the left side

2 x^{2} - 8 x = 0

Factor

2 x^{2} - 8 x : 2 x (x - 4)

2 x (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = 0, x = 4

x^{2} + 7 x + 10 = 0

2 x^{2} + 16 = 0

3 (x + 2)^{2} = 48

- 3 (3 h - 1) \leq - 7 h - 5

(\frac{3 x ^{- 1}}{4 y ^{- 1}})^{- 2}

What are the solutions to the equation 2x^2=8x ?
The solutions to the equation 2x^2=8x are x=0,x=4
Find the zeros of 2x^2=8x
The zeros of 2x^2=8x are x=0,x=4