What are the solutions to the equation 2x=x^2-3 ?

The solutions to the equation 2x=x^2-3 are x=3,x=-1

Find the zeros of 2x=x^2-3

The zeros of 2x=x^2-3 are x=3,x=-1

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2 x = x^{2} - 3

x = 3, x = - 1

Solution steps

2 x = x^{2} - 3

Switch sides

x^{2} - 3 = 2 x

Move

2 x

to the left side

x^{2} - 3 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

x = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

x^{2} + 10 x - 24

\frac{10 k + 40}{k ^{2} - k - 20}

- 9 (x + 4) + 2 x + 5 = 8 x + 10

10 x^{2} + x = 2

\frac{4}{8} = \frac{x}{10}

What are the solutions to the equation 2x=x^2-3 ?
The solutions to the equation 2x=x^2-3 are x=3,x=-1
Find the zeros of 2x=x^2-3
The zeros of 2x=x^2-3 are x=3,x=-1