What are the solutions to the equation x^2+2x-14=-12 ?

The solutions to the equation x^2+2x-14=-12 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of x^2+2x-14=-12

The zeros of x^2+2x-14=-12 are x=-1+sqrt(3),x=-1-sqrt(3)

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x^{2} + 2 x - 14 = - 12

x = - 1 + 3, x = - 1 - 3

Solution steps

x^{2} + 2 x - 14 = - 12

Move

12

to the left side

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

x^{3} - 4 x^{2} + 5 x - 20

(- 2)^{- 4}

5 (3 x - 10) (x - 10) = 1435

45 + 25

\frac{x}{- 4} \geq - 1

What are the solutions to the equation x^2+2x-14=-12 ?
The solutions to the equation x^2+2x-14=-12 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of x^2+2x-14=-12
The zeros of x^2+2x-14=-12 are x=-1+sqrt(3),x=-1-sqrt(3)