What are the solutions to the equation 5x^2-2x-7=0 ?

The solutions to the equation 5x^2-2x-7=0 are x= 7/5 ,x=-1

Find the zeros of 5x^2-2x-7=0

The zeros of 5x^2-2x-7=0 are x= 7/5 ,x=-1

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5 x^{2} - 2 x - 7 = 0

x = \frac{7}{5}, x = - 1

Solution steps

5 x^{2} - 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 7 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 7) = 12

x_{1, 2} = \frac{- ( - 2 ) \pm 12}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 12}{2 \cdot 5}

x = \frac{- ( - 2 ) + 12}{2 \cdot 5} : \frac{7}{5}

x = \frac{- ( - 2 ) - 12}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = \frac{7}{5}, x = - 1

8 a x - 56 a

X^{2} = 25

7 \cdot 21

12 m^{2} + 11 m = 15

4 - 2 x + 6 = 10 - 9 x + 7

What are the solutions to the equation 5x^2-2x-7=0 ?
The solutions to the equation 5x^2-2x-7=0 are x= 7/5 ,x=-1
Find the zeros of 5x^2-2x-7=0
The zeros of 5x^2-2x-7=0 are x= 7/5 ,x=-1