What are the solutions to the equation (x-4)^2=-3 ?

The solutions to the equation (x-4)^2=-3 are x=sqrt(3)i+4,x=-sqrt(3)i+4

Find the zeros of (x-4)^2=-3

The zeros of (x-4)^2=-3 are x=sqrt(3)i+4,x=-sqrt(3)i+4

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(x - 4)^{2} = - 3

x = 3 i + 4, x = - 3 i + 4

Solution steps

(x - 4)^{2} = - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 3 : x = 3 i + 4

Solve

x - 4 = - - 3 : x = - 3 i + 4

The solutions to the quadratic equation are:

x = 3 i + 4, x = - 3 i + 4

2 x^{2} + 15 x - 9 = - 26

8 = 2 + q

256 e^{- 4}

(\frac{3}{5})^{2}

9 z^{2} + 18 z - a z - 2 a

What are the solutions to the equation (x-4)^2=-3 ?
The solutions to the equation (x-4)^2=-3 are x=sqrt(3)i+4,x=-sqrt(3)i+4
Find the zeros of (x-4)^2=-3
The zeros of (x-4)^2=-3 are x=sqrt(3)i+4,x=-sqrt(3)i+4