What are the solutions to the equation 2x^2+15x-9=-26 ?

The solutions to the equation 2x^2+15x-9=-26 are x=(-15+sqrt(89))/4 ,x=(-15-sqrt(89))/4

Find the zeros of 2x^2+15x-9=-26

The zeros of 2x^2+15x-9=-26 are x=(-15+sqrt(89))/4 ,x=(-15-sqrt(89))/4

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2 x^{2} + 15 x - 9 = - 26

x = \frac{- 15 + 89}{4}, x = \frac{- 15 - 89}{4}

Solution steps

2 x^{2} + 15 x - 9 = - 26

Move

26

to the left side

2 x^{2} + 15 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 2 \cdot 17}{2 \cdot 2}

1 5^{2} - 4 \cdot 2 \cdot 17 = 89

x_{1, 2} = \frac{- 15 \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 15 + 89}{2 \cdot 2}, x_{2} = \frac{- 15 - 89}{2 \cdot 2}

x = \frac{- 15 + 89}{2 \cdot 2} : \frac{- 15 + 89}{4}

x = \frac{- 15 - 89}{2 \cdot 2} : \frac{- 15 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{- 15 + 89}{4}, x = \frac{- 15 - 89}{4}

8 = 2 + q

256 e^{- 4}

(\frac{3}{5})^{2}

9 z^{2} + 18 z - a z - 2 a

y^{2} - 10 y + 24 = 0

What are the solutions to the equation 2x^2+15x-9=-26 ?
The solutions to the equation 2x^2+15x-9=-26 are x=(-15+sqrt(89))/4 ,x=(-15-sqrt(89))/4
Find the zeros of 2x^2+15x-9=-26
The zeros of 2x^2+15x-9=-26 are x=(-15+sqrt(89))/4 ,x=(-15-sqrt(89))/4