What are the solutions to the equation (x+7)(x-3)=24 ?

The solutions to the equation (x+7)(x-3)=24 are x=5,x=-9

Find the zeros of (x+7)(x-3)=24

The zeros of (x+7)(x-3)=24 are x=5,x=-9

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(x + 7) (x - 3) = 24

x = 5, x = - 9

Solution steps

(x + 7) (x - 3) = 24

Expand

(x + 7) (x - 3) : x^{2} + 4 x - 21

x^{2} + 4 x - 21 = 24

Move

24

to the left side

x^{2} + 4 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 45) = 14

x_{1, 2} = \frac{- 4 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 14}{2 \cdot 1}, x_{2} = \frac{- 4 - 14}{2 \cdot 1}

x = \frac{- 4 + 14}{2 \cdot 1} : 5

x = \frac{- 4 - 14}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

81 x^{2} - 36 x + 4 = 0

(\frac{7}{10})^{2}

x^{2} - 90 x - 16200 = 0

\frac{1}{9} - \frac{1}{12}

610 = \frac{20}{2} [2 a + (20 - 1) 3]

What are the solutions to the equation (x+7)(x-3)=24 ?
The solutions to the equation (x+7)(x-3)=24 are x=5,x=-9
Find the zeros of (x+7)(x-3)=24
The zeros of (x+7)(x-3)=24 are x=5,x=-9