What are the solutions to the equation (x+50)^2=4x^2 ?

The solutions to the equation (x+50)^2=4x^2 are x=-50/3 ,x=50

Find the zeros of (x+50)^2=4x^2

The zeros of (x+50)^2=4x^2 are x=-50/3 ,x=50

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(x + 50)^{2} = 4 x^{2}

x = - \frac{50}{3}, x = 50

Solution steps

(x + 50)^{2} = 4 x^{2}

Expand

(x + 50)^{2} : x^{2} + 100 x + 2500

x^{2} + 100 x + 2500 = 4 x^{2}

Move

4 x^{2}

to the left side

- 3 x^{2} + 100 x + 2500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 3 ) \cdot 2500}{2 ( - 3 )}

10 0^{2} - 4 (- 3) \cdot 2500 = 200

x_{1, 2} = \frac{- 100 \pm 200}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 100 + 200}{2 ( - 3 )}, x_{2} = \frac{- 100 - 200}{2 ( - 3 )}

x = \frac{- 100 + 200}{2 ( - 3 )} : - \frac{50}{3}

x = \frac{- 100 - 200}{2 ( - 3 )} : 50

The solutions to the quadratic equation are:

x = - \frac{50}{3}, x = 50

\frac{x + 1}{x - 3} \leq 5

6 n - 2 (4 n + 7) + 4 = - 2

312 + 775 - 54

(x - 3) (x + 4) = 0

6 - 2

What are the solutions to the equation (x+50)^2=4x^2 ?
The solutions to the equation (x+50)^2=4x^2 are x=-50/3 ,x=50
Find the zeros of (x+50)^2=4x^2
The zeros of (x+50)^2=4x^2 are x=-50/3 ,x=50