What is |4-x^2|<((x+7))/2 ?

The solution to |4-x^2|<((x+7))/2 is -5/2 <x<-1\lor 1/2 <x<3

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|4-x^2|<((x+7))/2

4 - x^{2} < \frac{( x + 7 )}{2}

- \frac{5}{2} < x < - 1 or \frac{1}{2} < x < 3

Solution steps

4 - x^{2} < \frac{x + 7}{2}

Find positive and negative intervals

x < - 2, - 2 \leq x \leq 2, x > 2

Solve the inequality for each interval

- \frac{5}{2} < x < - 2 or (- 2 \leq x < - 1 or \frac{1}{2} < x \leq 2) or 2 < x < 3

Merge Overlapping Intervals

- \frac{5}{2} < x < - 1 or \frac{1}{2} < x < 3

n^{2} - 2 n x - 8 x^{2}

- 0.2 x^{2} + 0.1 x + 0.04 = 0

x (x - 6) = 91

7 x - 7 = 17 - 7 x

- 9 - (- 5)

What is |4-x^2|<((x+7))/2 ?
The solution to |4-x^2|<((x+7))/2 is -5/2 <x<-1\lor 1/2 <x<3