What are the solutions to the equation 0=x^2+4x+7 ?

The solutions to the equation 0=x^2+4x+7 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

Find the zeros of 0=x^2+4x+7

The zeros of 0=x^2+4x+7 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

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0 = x^{2} + 4 x + 7

x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

0 = x^{2} + 4 x + 7

Switch sides

x^{2} + 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 7 : 23 i

x_{1, 2} = \frac{- 4 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 3 i}{2 \cdot 1}

x = \frac{- 4 + 2 3 i}{2 \cdot 1} : - 2 + 3 i

x = \frac{- 4 - 2 3 i}{2 \cdot 1} : - 2 - 3 i

The solutions to the quadratic equation are:

x = - 2 + 3 i, x = - 2 - 3 i

4 x^{2} = 25

- 52 \leq 8

16 x^{2} + 40 x = - 25

(x - 2) (x - 5) (x - 6) \leq 0

- 1.6 t + 16 = 0

What are the solutions to the equation 0=x^2+4x+7 ?
The solutions to the equation 0=x^2+4x+7 are x=-2+sqrt(3)i,x=-2-sqrt(3)i
Find the zeros of 0=x^2+4x+7
The zeros of 0=x^2+4x+7 are x=-2+sqrt(3)i,x=-2-sqrt(3)i