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Popular >

y^2+4y-5=0

Solution

y^{2} + 4 y - 5 = 0

Solution

y = 1, y = - 5

Solution steps

y^{2} + 4 y - 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

y_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 4 + 6}{2 \cdot 1}, y_{2} = \frac{- 4 - 6}{2 \cdot 1}

y = \frac{- 4 + 6}{2 \cdot 1} : 1

y = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

y = 1, y = - 5

Popular Examples

1240=a*0.302734375^{20}

1240 = a \cdot 0.30273437 5^{20}

2 = \frac{3 x + 17}{4}

simplify (1.01*10^{-14})/(6.8*10^{-4)}simplify

\frac{1.01 \cdot 1 0 ^{- 14}}{6.8 \cdot 1 0 ^{- 4}}

v^{2} + 6 v + 9 = 0

2x(x+8)=(x-5)(x+8)

2 x (x + 8) = (x - 5) (x + 8)

Frequently Asked Questions (FAQ)

What are the solutions to the equation y^2+4y-5=0 ?
The solutions to the equation y^2+4y-5=0 are y=1,y=-5
Find the zeros of y^2+4y-5=0
The zeros of y^2+4y-5=0 are y=1,y=-5