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Popular >

integral from 2 to 3 of (x^2-4)

Solution

\int_{2}^{3} (x^{2} - 4) d x

Solution

\frac{7}{3}

+1

Solution steps

\int_{2}^{3} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{3} x^{2} d x - \int_{2}^{3} 4 d x

\int_{2}^{3} x^{2} d x = \frac{19}{3}

\int_{2}^{3} 4 d x = 4

= \frac{19}{3} - 4

Simplify

\frac{19}{3} - 4 : \frac{7}{3}

= \frac{7}{3}

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integral of (sqrt(3x+2))

\int (3 x + 2) d x

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(\partial)/(\partial x)(sin^2(2x+3y))

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integral from 0 to 1 of x^2(x^3-2)^3

\int_{0}^{1} x^{2} (x^{3} - 2)^{3} d x

Frequently Asked Questions (FAQ)

What is the integral from 2 to 3 of (x^2-4) ?
The integral from 2 to 3 of (x^2-4) is 7/3