What is the integral of sec(x)tan(x)-9e^x ?

The integral of sec(x)tan(x)-9e^x is sec(x)-9e^x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sec(x)tan(x)-9e^x

\int sec (x) tan (x) - 9 e^{x} d x

sec (x) - 9 e^{x} + C

Solution steps

\int sec (x) tan (x) - 9 e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec (x) tan (x) d x - \int 9 e^{x} d x

\int sec (x) tan (x) d x = sec (x)

\int 9 e^{x} d x = 9 e^{x}

= sec (x) - 9 e^{x}

Add a constant to the solution

= sec (x) - 9 e^{x} + C

\int_{1}^{3} x^{2} e^{x} d x

f (x) = x^{2}, at x = - \frac{1}{4}

y^{^{'}} - 2 x y - 8 = 0

e^{3 (t + 1)}

y = x (3 x - 2)^{4}

What is the integral of sec(x)tan(x)-9e^x ?
The integral of sec(x)tan(x)-9e^x is sec(x)-9e^x+C