en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=t^2-y

Solution

y^{^{'}} = t^{2} - y

Solution

y = t^{2} - 2 (t - 1) + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) = t^{2} - y

Solve linear ODE:

y = t^{2} - 2 (t - 1) + \frac{c _{1}}{e ^{t}}

y = t^{2} - 2 (t - 1) + \frac{c _{1}}{e ^{t}}

Popular Examples

derivative of arccos(3/x)

\frac{d}{d x} (arccos (\frac{3}{x}))

7 y^{^{''}} + 4 y^{^{'}} = 0

integral of (t^2+2)^3

\int (t^{2} + 2)^{3} d t

d/(dt)(6sin(t))

\frac{d}{d t} (6 sin (t))

tangent of y=4x^2 tangent of

y = 4 x^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=t^2-y ?
The solution for y^'=t^2-y is y=t^2-2(t-1)+(c_{1})/(e^t)