What is area x=y^2+6,y= x/2-3/2 ?

The answer to area x=y^2+6,y= x/2-3/2 is No Solution

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area x=y^2+6,y= x/2-3/2

area

x = y^{2} + 6, y = \frac{x}{2} - \frac{3}{2}

No Solution

Solution steps

Isolate

y

for

x = y^{2} + 6 : y = x - 6, y = - x - 6

f_{1} (x) = x - 6

f_{2} (x) = - x - 6

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x - 6 = - x - 6 : x = 6

x - 6 = \frac{x}{2} - \frac{3}{2} :

No Solution for

x \in R

- x - 6 = \frac{x}{2} - \frac{3}{2} :

No Solution for

x \in R

Curves not bounded

= No Solution

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What is area x=y^2+6,y= x/2-3/2 ?
The answer to area x=y^2+6,y= x/2-3/2 is No Solution