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Popular >

y^2y^'=y^2

Solution

y^{2} y^{^{'}} = y^{2}

Solution

y = t + c_{1}

Solution steps

y^{2} y^{'} (t) = y^{2}

Isolate

y^{'} (t) : y^{'} (t) = 1

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 1 d t

\int 1 d t = t + c_{1}

y = t + c_{1}

Popular Examples

tangent of f(x)=x^2-2x tangent of

f (x) = x^{2} - 2 x

integral of (x^3)/(sqrt(x^2+9))

\int \frac{x ^{3}}{x ^{2} + 9} d x

derivative of (-2x^2-2/((x-1)^2(x+1)^2))

\frac{d}{d x} (\frac{- 2 x ^{2} - 2}{( x - 1 ) ^{2} ( x + 1 ) ^{2}})

area x=(y-1)^2,x=13-y^2 area

x = (y - 1)^{2}, x = 13 - y^{2}

integral of (2x)/(e^{2x)}

\int \frac{2 x}{e ^{2 x}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^2y^'=y^2 ?
The solution for y^2y^'=y^2 is y=t+c_{1}