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Popular >

xy^'+2y=3x,y(1)=5

Solution

x y^{^{'}} + 2 y = 3 x, y (1) = 5

Solution

y = x + \frac{4}{x ^{2}}

Solution steps

x y^{'} (x) + 2 y = 3 x

Solve linear ODE:

y = x + \frac{4}{x ^{2}}

y = x + \frac{4}{x ^{2}}

Popular Examples

integral of x/((x^2+2)^{4/3)}

\int \frac{x}{( x ^{2} + 2 ) ^{\frac{4}{3}}} d x

y^{^{'}} = 3 y - y^{2}

derivative of csqrt(x)derivative of

c x

y^'-4/x y=(y^3)/(x^3),y(1)=1

y^{^{'}} - \frac{4}{x} y = \frac{y ^{3}}{x ^{3}}, y (1) = 1

derivative of 7/10 x^2+4x^3

\frac{d}{d x} (\frac{7}{10} x^{2} + 4 x^{3})

Frequently Asked Questions (FAQ)

What is the solution for xy^'+2y=3x,y(1)=5 ?
The solution for xy^'+2y=3x,y(1)=5 is y=x+4/(x^2)