What is the derivative of (x^2-y^2/(x^2+y^2)) ?

The derivative of (x^2-y^2/(x^2+y^2)) is (-4x^2y\frac{dy)/(dx)+4xy^2}{(x^2+y^2)^2}

What is the first derivative of (x^2-y^2/(x^2+y^2)) ?

The first derivative of (x^2-y^2/(x^2+y^2)) is (-4x^2y\frac{dy)/(dx)+4xy^2}{(x^2+y^2)^2}

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Popular >

\frac{d}{d x} (\frac{x ^{2} - y ^{2}}{x ^{2} + y ^{2}})

\frac{- 4 x ^{2} y \frac{d y}{d x} + 4 x y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - y ^{2}}{x ^{2} + y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - y ^{2} ) ( x ^{2} + y ^{2} ) - \frac{d}{d x} ( x ^{2} + y ^{2} ) ( x ^{2} - y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

\frac{d}{d x} (x^{2} - y^{2}) = 2 x - 2 y \frac{d y}{d x}

\frac{d}{d x} (x^{2} + y^{2}) = 2 x + 2 y \frac{d y}{d x}

= \frac{( 2 x - 2 y \frac{d y}{d x} ) ( x ^{2} + y ^{2} ) - ( 2 x + 2 y \frac{d y}{d x} ) ( x ^{2} - y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

Expand

(2 x - 2 y \frac{d y}{d x}) (x^{2} + y^{2}) - (2 x + 2 y \frac{d y}{d x}) (x^{2} - y^{2}) : - 4 x^{2} y \frac{d y}{d x} + 4 x y^{2}

= \frac{- 4 x ^{2} y \frac{d y}{d x} + 4 x y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

\frac{d}{d x} (6 (2 x - 9)^{5})

(5 x + y e^{(\frac{y}{x})}) d x - x e^{\frac{y}{x}} d y = 0

\frac{\partial}{\partial x} (ln (cos (x y) + 2))

\int tan^{4} (x) + tan^{6} (x) d x

h \to 0 lim (\frac{1}{5 - h})

What is the derivative of (x^2-y^2/(x^2+y^2)) ?
The derivative of (x^2-y^2/(x^2+y^2)) is (-4x^2y\frac{dy)/(dx)+4xy^2}{(x^2+y^2)^2}
What is the first derivative of (x^2-y^2/(x^2+y^2)) ?
The first derivative of (x^2-y^2/(x^2+y^2)) is (-4x^2y\frac{dy)/(dx)+4xy^2}{(x^2+y^2)^2}